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8p^2=5-12p
We move all terms to the left:
8p^2-(5-12p)=0
We add all the numbers together, and all the variables
8p^2-(-12p+5)=0
We get rid of parentheses
8p^2+12p-5=0
a = 8; b = 12; c = -5;
Δ = b2-4ac
Δ = 122-4·8·(-5)
Δ = 304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{304}=\sqrt{16*19}=\sqrt{16}*\sqrt{19}=4\sqrt{19}$$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-4\sqrt{19}}{2*8}=\frac{-12-4\sqrt{19}}{16} $$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+4\sqrt{19}}{2*8}=\frac{-12+4\sqrt{19}}{16} $
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